1. Basic Predicate Calculus
1.1 An overview of the specification language Gallina
A formal development in Gallina consists in a sequence of declarations and definitions.
1.1.1 Declarations
A declaration associates a name with a specification.
A name corresponds roughly to an identifier in a programming
language, i.e. to a string of letters, digits, and a few ASCII symbols like
underscore (_
) and prime ('
), starting with a letter.
We use case distinction, so that the names A
and a
are distinct.
Certain strings are reserved as key-words of Coq, and thus are forbidden
as user identifiers.
A specification is a formal expression which classifies the notion which is
being declared. There are basically three kinds of specifications:
logical propositions, mathematical collections, and
abstract types. They are classified by the three basic sorts
of the system, called respectively Prop
, Set
, and
Type
, which are themselves atomic abstract types.
Every valid expression e in Gallina is associated with a specification,
itself a valid expression, called its type τ(E). We write
e:τ(E) for the judgment that e is of type E.
You may request Coq to return to you the type of a valid expression by using
the command Check
:
0
: nat
Thus we know that the identifier O
(the name ‘O’, not to be
confused with the numeral ‘0’ which is not a proper identifier!) is
known in the current context, and that its type is the specification
nat
. This specification is itself classified as a mathematical
collection, as we may readily check:
nat
: Set
The specification Set
is an abstract type, one of the basic
sorts of the Gallina language, whereas the notions nat and O are
notions which are defined in the arithmetic prelude,
automatically loaded when running the Coq system.
We start by introducing a so-called section name. The role of sections is to structure the modelisation by limiting the scope of parameters, hypotheses and definitions. It will also give a convenient way to reset part of the development.
With what we already know, we may now enter in the system a declaration, corresponding to the informal mathematics let n be a natural number.
n is declared
If we want to translate a more precise statement, such as
let n be a positive natural number,
we have to add another declaration, which will declare explicitly the
hypothesis Pos_n
, with specification the proper logical
proposition:
Pos_n is declared
Indeed we may check that the relation gt
is known with the right type
in the current context:
gt
: nat -> nat -> Prop
which tells us that gt is a function expecting two arguments of type nat in order to build a logical proposition. What happens here is similar to what we are used to in a functional programming language: we may compose the (specification) type nat with the (abstract) type Prop of logical propositions through the arrow function constructor, in order to get a functional type nat -> Prop:
nat -> Prop
: Type
which may be composed once more with nat
in order to obtain the
type nat -> nat -> Prop of binary relations over natural numbers.
Actually the type nat -> nat -> Prop is an abbreviation for
nat -> (nat -> Prop).
Functional notions may be composed in the usual way. An expression f
of type A→ B may be applied to an expression e of type A in order
to form the expression (f e) of type B. Here we get that
the expression (gt n)
is well-formed of type nat -> Prop,
and thus that the expression (gt n O)
, which abbreviates
((gt n) O)
, is a well-formed proposition.
n > 0
: Prop
1.1.2 Definitions
The initial prelude contains a few arithmetic definitions: nat is defined as a mathematical collection (type Set), constants O, S, plus, are defined as objects of types respectively nat, nat -> nat, and nat -> nat -> nat. You may introduce new definitions, which link a name to a well-typed value. For instance, we may introduce the constant one as being defined to be equal to the successor of zero:
one is defined
We may optionally indicate the required type:
two is defined
Actually Coq allows several possible syntaxes:
three is defined
Here is a way to define the doubling function, which expects an
argument m
of type nat
in order to build its result as
(plus m m)
:
double is defined
This introduces the constant double defined as the expression fun m : nat => plus m m. The abstraction introduced by fun is explained as follows. The expression fun x : A => e is well formed of type A -> B in a context whenever the expression e is well-formed of type B in the given context to which we add the declaration that x is of type A. Here x is a bound, or dummy variable in the expression fun x : A => e. For instance we could as well have defined double as fun n : nat => (plus n n).
Bound (local) variables and free (global) variables may be mixed.
For instance, we may define the function which adds the constant n
to its argument as
add_n is defined
However, note that here we may not rename the formal argument m into n without capturing the free occurrence of n, and thus changing the meaning of the defined notion.
Binding operations are well known for instance in logic, where they are called quantifiers. Thus we may universally quantify a proposition such as m>0 in order to get a universal proposition ∀ m· m>0. Indeed this operator is available in Coq, with the following syntax: forall m : nat, gt m O. Similarly to the case of the functional abstraction binding, we are obliged to declare explicitly the type of the quantified variable. We check:
forall m : nat, m > 0
: Prop
1.2 Introduction to the proof engine: Minimal Logic
In the following, we are going to consider various propositions, built
from atomic propositions A, B, C. This may be done easily, by
introducing these atoms as global variables declared of type Prop
.
It is easy to declare several names with the same specification:
Coq < Variables A B C : Prop.
A is declared
B is declared
C is declared
We shall consider simple implications, such as A→ B, read as “A implies B”. Note that we overload the arrow symbol, which has been used above as the functionality type constructor, and which may be used as well as propositional connective:
A -> B
: Prop
Let us now embark on a simple proof. We want to prove the easy tautology
((A→ (B→ C))→ (A→ B)→ (A→ C).
We enter the proof engine by the command
Goal
, followed by the conjecture we want to verify:
1 subgoal
A, B, C : Prop
============================
(A -> B -> C) -> (A -> B) -> A -> C
The system displays the current goal below a double line, local hypotheses
(there are none initially) being displayed above the line. We call
the combination of local hypotheses with a goal a judgment.
We are now in an inner
loop of the system, in proof mode.
New commands are available in this
mode, such as tactics, which are proof combining primitives.
A tactic operates on the current goal by attempting to construct a proof
of the corresponding judgment, possibly from proofs of some
hypothetical judgments, which are then added to the current
list of conjectured judgments.
For instance, the intro
tactic is applicable to any judgment
whose goal is an implication, by moving the proposition to the left
of the application to the list of local hypotheses:
1 subgoal
A, B, C : Prop
H : A -> B -> C
============================
(A -> B) -> A -> C
Several introductions may be done in one step:
1 subgoal
A, B, C : Prop
H : A -> B -> C
H' : A -> B
HA : A
============================
C
We notice that C, the current goal, may be obtained from hypothesis
H
, provided the truth of A and B are established.
The tactic apply
implements this piece of reasoning:
2 subgoals
A, B, C : Prop
H : A -> B -> C
H' : A -> B
HA : A
============================
A
subgoal 2 is:
B
We are now in the situation where we have two judgments as conjectures
that remain to be proved. Only the first is listed in full, for the
others the system displays only the corresponding subgoal, without its
local hypotheses list. Note that apply
has kept the local
hypotheses of its father judgment, which are still available for
the judgments it generated.
In order to solve the current goal, we just have to notice that it is exactly available as hypothesis HA:
1 subgoal
A, B, C : Prop
H : A -> B -> C
H' : A -> B
HA : A
============================
B
Now H′ applies:
1 subgoal
A, B, C : Prop
H : A -> B -> C
H' : A -> B
HA : A
============================
A
And we may now conclude the proof as before, with exact HA.
Actually, we may not bother with the name HA
, and just state that
the current goal is solvable from the current local assumptions:
No more subgoals.
The proof is now finished. We are now going to ask Coq’s kernel to check and save the proof.
Unnamed_thm is defined
Let us redo the same proof with a few variations. First of all we may name the initial goal as a conjectured lemma:
1 subgoal
A, B, C : Prop
============================
(A -> B -> C) -> (A -> B) -> A -> C
Next, we may omit the names of local assumptions created by the introduction tactics, they can be automatically created by the proof engine as new non-clashing names.
1 subgoal
A, B, C : Prop
H : A -> B -> C
H0 : A -> B
H1 : A
============================
C
The intros
tactic, with no arguments, effects as many individual
applications of intro
as is legal.
Then, we may compose several tactics together in sequence, or in parallel, through tacticals, that is tactic combinators. The main constructions are the following:
- T1 ; T2 (read T1 then T2) applies tactic T1 to the current goal, and then tactic T2 to all the subgoals generated by T1.
- T; [T1 | T2 | ... | Tn] applies tactic T to the current goal, and then tactic T1 to the first newly generated subgoal, ..., Tn to the nth.
We may thus complete the proof of distr_impl
with one composite tactic:
No more subgoals.
You should be aware however that relying on automatically generated names is not robust to slight updates to this proof script. Consequently, it is discouraged in finished proof scripts. As for the composition of tactics with : it may hinder the readability of the proof script and it is also harder to see what’s going on when replaying the proof because composed tactics are evaluated in one go.
Actually, such an easy combination of tactics intro
, apply
and assumption
may be found completely automatically by an automatic
tactic, called auto
, without user guidance:
1 subgoal
A, B, C : Prop
============================
(A -> B -> C) -> (A -> B) -> A -> C
Coq < auto.
No more subgoals.
Let us now save lemma distr_impl
:
distr_impl is defined
1.3 Propositional Calculus
1.3.1 Conjunction
We have seen how intro
and apply
tactics could be combined
in order to prove implicational statements. More generally, Coq favors a style
of reasoning, called Natural Deduction, which decomposes reasoning into
so called introduction rules, which tell how to prove a goal whose main
operator is a given propositional connective, and elimination rules,
which tell how to use an hypothesis whose main operator is the propositional
connective. Let us show how to use these ideas for the propositional connectives
/\
and \/
.
1 subgoal
A, B, C : Prop
============================
A /\ B -> B /\ A
Coq < intro H.
1 subgoal
A, B, C : Prop
H : A /\ B
============================
B /\ A
We make use of the conjunctive hypothesis H
with the elim
tactic,
which breaks it into its components:
1 subgoal
A, B, C : Prop
H : A /\ B
============================
A -> B -> B /\ A
We now use the conjunction introduction tactic split
, which splits the
conjunctive goal into the two subgoals:
2 subgoals
A, B, C : Prop
H : A /\ B
H0 : A
H1 : B
============================
B
subgoal 2 is:
A
and the proof is now trivial. Indeed, the whole proof is obtainable as follows:
1 subgoal
A, B, C : Prop
============================
A /\ B -> B /\ A
Coq < intro H; elim H; auto.
No more subgoals.
Coq < Qed.
and_commutative is defined
The tactic auto
succeeded here because it knows as a hint the
conjunction introduction operator conj
conj
: forall A B : Prop, A -> B -> A /\ B
Actually, the tactic split
is just an abbreviation for apply conj.
What we have just seen is that the auto
tactic is more powerful than
just a simple application of local hypotheses; it tries to apply as well
lemmas which have been specified as hints. A
Hint Resolve
command registers a
lemma as a hint to be used from now on by the auto
tactic, whose power
may thus be incrementally augmented.
1.3.2 Disjunction
In a similar fashion, let us consider disjunction:
1 subgoal
A, B, C : Prop
============================
A \/ B -> B \/ A
Coq < intro H; elim H.
2 subgoals
A, B, C : Prop
H : A \/ B
============================
A -> B \/ A
subgoal 2 is:
B -> B \/ A
Let us prove the first subgoal in detail. We use intro
in order to
be left to prove B\/A
from A
:
2 subgoals
A, B, C : Prop
H : A \/ B
HA : A
============================
B \/ A
subgoal 2 is:
B -> B \/ A
Here the hypothesis H
is not needed anymore. We could choose to
actually erase it with the tactic clear
; in this simple proof it
does not really matter, but in bigger proof developments it is useful to
clear away unnecessary hypotheses which may clutter your screen.
2 subgoals
A, B, C : Prop
HA : A
============================
B \/ A
subgoal 2 is:
B -> B \/ A
The tactic destruct
combines the effects of elim
, intros
,
and clear
:
1 subgoal
A, B, C : Prop
============================
A \/ B -> B \/ A
Coq < intros H; destruct H.
2 subgoals
A, B, C : Prop
H : A
============================
B \/ A
subgoal 2 is:
B \/ A
The disjunction connective has two introduction rules, since P\/Q
may be obtained from P
or from Q
; the two corresponding
proof constructors are called respectively or_introl
and
or_intror
; they are applied to the current goal by tactics
left
and right
respectively. For instance:
2 subgoals
A, B, C : Prop
H : A
============================
A
subgoal 2 is:
B \/ A
Coq < trivial.
1 subgoal
A, B, C : Prop
H : B
============================
B \/ A
The tactic trivial
works like auto
with the hints
database, but it only tries those tactics that can solve the goal in one
step.
As before, all these tedious elementary steps may be performed automatically, as shown for the second symmetric case:
No more subgoals.
However, auto
alone does not succeed in proving the full lemma, because
it does not try any elimination step.
It is a bit disappointing that auto
is not able to prove automatically
such a simple tautology. The reason is that we want to keep
auto
efficient, so that it is always effective to use.
1.3.3 Tauto
A complete tactic for propositional
tautologies is indeed available in Coq as the tauto
tactic.
1 subgoal
A, B, C : Prop
============================
A \/ B -> B \/ A
Coq < tauto.
No more subgoals.
Coq < Qed.
or_commutative is defined
It is possible to inspect the actual proof tree constructed by tauto
,
using a standard command of the system, which prints the value of any notion
currently defined in the context:
or_commutative =
fun H : A \/ B =>
or_ind (fun H0 : A => or_intror H0)
(fun H0 : B => or_introl H0) H
: A \/ B -> B \/ A
It is not easy to understand the notation for proof terms without some
explanations. The fun prefix, such as fun H : A\/B =>
,
corresponds
to intro H
, whereas a subterm such as
(or_intror
B H0)
corresponds to the sequence of tactics apply or_intror; exact H0
.
The generic combinator or_intror
needs to be instantiated by
the two properties B
and A
. Because A
can be
deduced from the type of H0
, only B
is printed.
The two instantiations are effected automatically by the tactic
apply
when pattern-matching a goal. The specialist will of course
recognize our proof term as a λ-term, used as notation for the
natural deduction proof term through the Curry-Howard isomorphism. The
naive user of Coq may safely ignore these formal details.
Let us exercise the tauto
tactic on a more complex example:
1 subgoal
A, B, C : Prop
============================
A -> B /\ C -> (A -> B) /\ (A -> C)
Coq < tauto.
No more subgoals.
Coq < Qed.
distr_and is defined
1.3.4 Classical reasoning
The tactic tauto
always comes back with an answer. Here is an example where it
fails:
1 subgoal
A, B, C : Prop
============================
((A -> B) -> A) -> A
Coq < try tauto.
1 subgoal
A, B, C : Prop
============================
((A -> B) -> A) -> A
Note the use of the try
tactical, which does nothing if its tactic
argument fails.
This may come as a surprise to someone familiar with classical reasoning.
Peirce’s lemma is true in Boolean logic, i.e. it evaluates to true
for
every truth-assignment to A
and B
. Indeed the double negation
of Peirce’s law may be proved in Coq using tauto
:
1 subgoal
A, B, C : Prop
============================
~ ~ (((A -> B) -> A) -> A)
Coq < tauto.
No more subgoals.
Coq < Qed.
NNPeirce is defined
In classical logic, the double negation of a proposition is equivalent to this
proposition, but in the constructive logic of Coq this is not so. If you
want to use classical logic in Coq, you have to import explicitly the
Classical
module, which will declare the axiom classic
of excluded middle, and classical tautologies such as de Morgan’s laws.
The Require
command is used to import a module from Coq’s library:
Coq < Check NNPP.
NNPP
: forall p : Prop, ~ ~ p -> p
and it is now easy (although admittedly not the most direct way) to prove a classical law such as Peirce’s:
1 subgoal
A, B, C : Prop
============================
((A -> B) -> A) -> A
Coq < apply NNPP; tauto.
No more subgoals.
Coq < Qed.
Peirce is defined
Here is one more example of propositional reasoning, in the shape of a Scottish puzzle. A private club has the following rules:
- Every non-scottish member wears red socks
- Every member wears a kilt or doesn’t wear red socks
- The married members don’t go out on Sunday
- A member goes out on Sunday if and only if he is Scottish
- Every member who wears a kilt is Scottish and married
- Every scottish member wears a kilt
Now, we show that these rules are so strict that no one can be accepted.
Coq < Variables Scottish RedSocks WearKilt Married GoOutSunday : Prop.
Scottish is declared
RedSocks is declared
WearKilt is declared
Married is declared
GoOutSunday is declared
Coq < Hypothesis rule1 : ~ Scottish -> RedSocks.
rule1 is declared
Coq < Hypothesis rule2 : WearKilt \/ ~ RedSocks.
rule2 is declared
Coq < Hypothesis rule3 : Married -> ~ GoOutSunday.
rule3 is declared
Coq < Hypothesis rule4 : GoOutSunday <-> Scottish.
rule4 is declared
Coq < Hypothesis rule5 : WearKilt -> Scottish /\ Married.
rule5 is declared
Coq < Hypothesis rule6 : Scottish -> WearKilt.
rule6 is declared
Coq < Lemma NoMember : False.
1 subgoal
A, B, C, Scottish, RedSocks, WearKilt, Married,
GoOutSunday : Prop
rule1 : ~ Scottish -> RedSocks
rule2 : WearKilt \/ ~ RedSocks
rule3 : Married -> ~ GoOutSunday
rule4 : GoOutSunday <-> Scottish
rule5 : WearKilt -> Scottish /\ Married
rule6 : Scottish -> WearKilt
============================
False
Coq < tauto.
No more subgoals.
Coq < Qed.
NoMember is defined
At that point NoMember
is a proof of the absurdity depending on
hypotheses.
We may end the section, in that case, the variables and hypotheses
will be discharged, and the type of NoMember
will be
generalised.
Coq < Check NoMember.
NoMember
: forall
Scottish RedSocks WearKilt Married
GoOutSunday : Prop,
(~ Scottish -> RedSocks) ->
WearKilt \/ ~ RedSocks ->
(Married -> ~ GoOutSunday) ->
GoOutSunday <-> Scottish ->
(WearKilt -> Scottish /\ Married) ->
(Scottish -> WearKilt) -> False
1.4 Predicate Calculus
Let us now move into predicate logic, and first of all into first-order predicate calculus. The essence of predicate calculus is that to try to prove theorems in the most abstract possible way, without using the definitions of the mathematical notions, but by formal manipulations of uninterpreted function and predicate symbols.
1.4.1 Sections and signatures
Usually one works in some domain of discourse, over which range the individual
variables and function symbols. In Coq, we speak in a language with a rich
variety of types, so we may mix several domains of discourse, in our
multi-sorted language. For the moment, we just do a few exercises, over a
domain of discourse D
axiomatised as a Set
, and we consider two
predicate symbols P
and R
over D
, of arities
1 and 2, respectively.
We start by assuming a domain of
discourse D
, and a binary relation R
over D
:
Coq < Variable D : Set.
D is declared
Coq < Variable R : D -> D -> Prop.
R is declared
As a simple example of predicate calculus reasoning, let us assume
that relation R
is symmetric and transitive, and let us show that
R
is reflexive in any point x
which has an R
successor.
Since we do not want to make the assumptions about R
global axioms of
a theory, but rather local hypotheses to a theorem, we open a specific
section to this effect.
Coq < Hypothesis R_symmetric : forall x y : D, R x y -> R y x.
R_symmetric is declared
Coq < Hypothesis R_transitive :
forall x y z : D, R x y -> R y z -> R x z.
R_transitive is declared
Note the syntax forall x : D,
which stands for universal quantification
∀ x : D.
1.4.2 Existential quantification
We now state our lemma, and enter proof mode.
1 subgoal
D : Set R : D -> D -> Prop
R_symmetric : forall x y : D, R x y -> R y x
R_transitive : forall x y z : D, R x y -> R y z -> R x z
============================
forall x : D, (exists y : D, R x y) -> R x x
The hypotheses that are local to the currently opened sections are listed as local hypotheses to the current goals. That is because these hypotheses are going to be discharged, as we shall see, when we shall close the corresponding sections.
Note the functional syntax for existential quantification. The existential
quantifier is built from the operator ex
, which expects a
predicate as argument:
ex
: forall A : Type, (A -> Prop) -> Prop
and the notation (exists x : D, P x)
is just concrete syntax for
the expression (ex D (fun x : D => P x))
.
Existential quantification is handled in Coq in a similar
fashion to the connectives /\
and \/
: it is introduced by
the proof combinator ex_intro
, which is invoked by the specific
tactic exists
, and its elimination provides a witness a : D
to
P
, together with an assumption h : (P a)
that indeed a
verifies P
. Let us see how this works on this simple example.
1 subgoal
D : Set R : D -> D -> Prop
R_symmetric : forall x y : D, R x y -> R y x
R_transitive : forall x y z : D, R x y -> R y z -> R x z
x : D
x_Rlinked : exists y : D, R x y
============================
R x x
Note that intros
treats universal quantification in the same way
as the premises of implications. Renaming of bound variables occurs
when it is needed; for instance, had we started with intro y
,
we would have obtained the goal:
1 subgoal
D : Set R : D -> D -> Prop
R_symmetric : forall x y : D, R x y -> R y x
R_transitive : forall x y z : D, R x y -> R y z -> R x z
y : D
============================
(exists y0 : D, R y y0) -> R y y
Let us now use the existential hypothesis x_Rlinked
to
exhibit an R-successor y of x. This is done in two steps, first with
elim
, then with intros
1 subgoal
D : Set R : D -> D -> Prop
R_symmetric : forall x y : D, R x y -> R y x
R_transitive : forall x y z : D, R x y -> R y z -> R x z
x : D
x_Rlinked : exists y : D, R x y
============================
forall x0 : D, R x x0 -> R x x
Coq < intros y Rxy.
1 subgoal
D : Set R : D -> D -> Prop
R_symmetric : forall x y : D, R x y -> R y x
R_transitive : forall x y z : D, R x y -> R y z -> R x z
x : D
x_Rlinked : exists y : D, R x y
y : D
Rxy : R x y
============================
R x x
Now we want to use R_transitive
. The apply
tactic will know
how to match x
with x
, and z
with x
, but needs
help on how to instantiate y
, which appear in the hypotheses of
R_transitive
, but not in its conclusion. We give the proper hint
to apply
in a with
clause, as follows:
2 subgoals
D : Set R : D -> D -> Prop
R_symmetric : forall x y : D, R x y -> R y x
R_transitive : forall x y z : D, R x y -> R y z -> R x z
x : D
x_Rlinked : exists y : D, R x y
y : D
Rxy : R x y
============================
R x y
subgoal 2 is:
R y x
The rest of the proof is routine:
1 subgoal
D : Set R : D -> D -> Prop
R_symmetric : forall x y : D, R x y -> R y x
R_transitive : forall x y z : D, R x y -> R y z -> R x z
x : D
x_Rlinked : exists y : D, R x y
y : D
Rxy : R x y
============================
R y x
Coq < apply R_symmetric; assumption.
No more subgoals.
Coq < Qed.
Let us now close the current section.
All the local hypotheses have been
discharged in the statement of refl_if
, which now becomes a general
theorem in the first-order language declared in section
Predicate_calculus
. In this particular example, section
R_sym_trans
has not been really useful, since we could have
instead stated theorem refl_if
in its general form, and done
basically the same proof, obtaining R_symmetric
and
R_transitive
as local hypotheses by initial intros
rather
than as global hypotheses in the context. But if we had pursued the
theory by proving more theorems about relation R
,
we would have obtained all general statements at the closing of the section,
with minimal dependencies on the hypotheses of symmetry and transitivity.
1.4.3 Paradoxes of classical predicate calculus
Let us illustrate this feature by pursuing our Predicate_calculus
section with an enrichment of our language: we declare a unary predicate
P
and a constant d
:
P is declared
Coq < Variable d : D.
d is declared
We shall now prove a well-known fact from first-order logic: a universal predicate is non-empty, or in other terms existential quantification follows from universal quantification.
1 subgoal
D : Set R : D -> D -> Prop P : D -> Prop d : D
============================
(forall x : D, P x) -> exists a : D, P a
Coq < intro UnivP.
1 subgoal
D : Set R : D -> D -> Prop P : D -> Prop d : D
UnivP : forall x : D, P x
============================
exists a : D, P a
First of all, notice the pair of parentheses around
forall x : D, P x
in
the statement of lemma weird
.
If we had omitted them, Coq’s parser would have interpreted the
statement as a truly trivial fact, since we would
postulate an x
verifying (P x)
. Here the situation is indeed
more problematic. If we have some element in Set
D
, we may
apply UnivP
to it and conclude, otherwise we are stuck. Indeed
such an element d
exists, but this is just by virtue of our
new signature. This points out a subtle difference between standard
predicate calculus and Coq. In standard first-order logic,
the equivalent of lemma weird
always holds,
because such a rule is wired in the inference rules for quantifiers, the
semantic justification being that the interpretation domain is assumed to
be non-empty. Whereas in Coq, where types are not assumed to be
systematically inhabited, lemma weird
only holds in signatures
which allow the explicit construction of an element in the domain of
the predicate.
Let us conclude the proof, in order to show the use of the exists
tactic:
No more subgoals.
Coq < Qed.
weird is defined
Another fact which illustrates the sometimes disconcerting rules of
classical
predicate calculus is Smullyan’s drinkers’ paradox: “In any non-empty
bar, there is a person such that if she drinks, then everyone drinks”.
We modelize the bar by Set D
, drinking by predicate P
.
We shall need classical reasoning. Instead of loading the Classical
module as we did above, we just state the law of excluded middle as a
local hypothesis schema at this point:
EM is declared
Coq < Lemma drinker : exists x : D, P x -> forall x : D, P x.
1 subgoal
D : Set R : D -> D -> Prop P : D -> Prop d : D
EM : forall A : Prop, A \/ ~ A
============================
exists x : D, P x -> forall x0 : D, P x0
The proof goes by cases on whether or not
there is someone who does not drink. Such reasoning by cases proceeds
by invoking the excluded middle principle, via elim
of the
proper instance of EM
:
2 subgoals
D : Set R : D -> D -> Prop P : D -> Prop d : D
EM : forall A : Prop, A \/ ~ A
============================
(exists x : D, ~ P x) ->
exists x : D, P x -> forall x0 : D, P x0
subgoal 2 is:
~ (exists x : D, ~ P x) ->
exists x : D, P x -> forall x0 : D, P x0
We first look at the first case. Let Tom be the non-drinker.
The following combines at once the effect of intros
and
destruct
:
2 subgoals
D : Set R : D -> D -> Prop P : D -> Prop d : D
EM : forall A : Prop, A \/ ~ A
Tom : D
Tom_does_not_drink : ~ P Tom
============================
exists x : D, P x -> forall x0 : D, P x0
subgoal 2 is:
~ (exists x : D, ~ P x) ->
exists x : D, P x -> forall x0 : D, P x0
We conclude in that case by considering Tom, since his drinking leads to a contradiction:
2 subgoals
D : Set R : D -> D -> Prop P : D -> Prop d : D
EM : forall A : Prop, A \/ ~ A
Tom : D
Tom_does_not_drink : ~ P Tom
Tom_drinks : P Tom
============================
forall x : D, P x
subgoal 2 is:
~ (exists x : D, ~ P x) ->
exists x : D, P x -> forall x0 : D, P x0
There are several ways in which we may eliminate a contradictory case;
in this case, we use contradiction
to let Coq find out the
two contradictory hypotheses:
1 subgoal
D : Set R : D -> D -> Prop P : D -> Prop d : D
EM : forall A : Prop, A \/ ~ A
============================
~ (exists x : D, ~ P x) ->
exists x : D, P x -> forall x0 : D, P x0
We now proceed with the second case, in which actually any person will do;
such a John Doe is given by the non-emptiness witness d
:
1 subgoal
D : Set R : D -> D -> Prop P : D -> Prop d : D
EM : forall A : Prop, A \/ ~ A
No_nondrinker : ~ (exists x : D, ~ P x)
d_drinks : P d
============================
forall x : D, P x
Now we consider any Dick in the bar, and reason by cases according to its drinking or not:
1 subgoal
D : Set R : D -> D -> Prop P : D -> Prop d : D
EM : forall A : Prop, A \/ ~ A
No_nondrinker : ~ (exists x : D, ~ P x)
d_drinks : P d
Dick : D
============================
~ P Dick -> P Dick
The only non-trivial case is again treated by contradiction:
1 subgoal
D : Set R : D -> D -> Prop P : D -> Prop d : D
EM : forall A : Prop, A \/ ~ A
No_nondrinker : ~ (exists x : D, ~ P x)
d_drinks : P d
Dick : D
Dick_does_not_drink : ~ P Dick
============================
exists x : D, ~ P x
Coq < exists Dick; trivial.
No more subgoals.
Coq < Qed.
drinker is defined
Now, let us close the main section and look at the complete statements we proved:
Coq < Check refl_if.
refl_if
: forall (D : Set) (R : D -> D -> Prop),
(forall x y : D, R x y -> R y x) ->
(forall x y z : D, R x y -> R y z -> R x z) ->
forall x : D, (exists y : D, R x y) -> R x x
Coq < Check weird.
weird
: forall (D : Set) (P : D -> Prop),
D -> (forall x : D, P x) -> exists a : D, P a
Coq < Check drinker.
drinker
: forall (D : Set) (P : D -> Prop),
D ->
(forall A : Prop, A \/ ~ A) ->
exists x : D, P x -> forall x0 : D, P x0
Note how the three theorems are completely generic in the most general
fashion;
the domain D
is discharged in all of them, R
is discharged in
refl_if
only, P
is discharged only in weird
and
drinker
, along with the hypothesis that D
is inhabited.
Finally, the excluded middle hypothesis is discharged only in
drinker
.
Note, too, that the name d
has vanished from
the statements of weird
and drinker
,
since Coq’s pretty-printer replaces
systematically a quantification such as forall d : D, E,
where d does not occur in E,
by the functional notation D -> E.
Similarly the name EM does not appear in drinker.
Actually, universal quantification, implication, as well as function formation, are all special cases of one general construct of type theory called dependent product. This is the mathematical construction corresponding to an indexed family of functions. A function f∈ Π x:D· Cx maps an element x of its domain D to its (indexed) codomain Cx. Thus a proof of ∀ x:D· Px is a function mapping an element x of D to a proof of proposition Px.
1.4.4 Flexible use of local assumptions
Very often during the course of a proof we want to retrieve a local
assumption and reintroduce it explicitly in the goal, for instance
in order to get a more general induction hypothesis. The tactic
generalize
is what is needed here:
Coq < Variables P Q : nat -> Prop.
P is declared
Q is declared
Coq < Variable R : nat -> nat -> Prop.
R is declared
Coq < Lemma PQR :
forall x y:nat, (R x x -> P x -> Q x) -> P x -> R x y -> Q x.
1 subgoal
P, Q : nat -> Prop R : nat -> nat -> Prop
============================
forall x y : nat,
(R x x -> P x -> Q x) -> P x -> R x y -> Q x
Coq < intros.
1 subgoal
P, Q : nat -> Prop R : nat -> nat -> Prop x, y : nat
H : R x x -> P x -> Q x
H0 : P x
H1 : R x y
============================
Q x
Coq < generalize H0.
1 subgoal
P, Q : nat -> Prop R : nat -> nat -> Prop x, y : nat
H : R x x -> P x -> Q x
H0 : P x
H1 : R x y
============================
P x -> Q x
Sometimes it may be convenient to state an intermediate fact.
The tactic assert
does this and introduces a new subgoal
for this fact to be proved first. The tactic enough
does
the same while keeping this goal for later.
1 subgoal
P, Q : nat -> Prop R : nat -> nat -> Prop x, y : nat
H : R x x -> P x -> Q x
H0 : P x
H1 : R x y
============================
R x x
We clean the goal by doing an Abort
command.
1.4.5 Equality
The basic equality provided in Coq is Leibniz equality, noted infix like x = y, when x and y are two expressions of type the same Set. The replacement of x by y in any term is effected by a variety of tactics, such as rewrite and replace.
Let us give a few examples of equality replacement. Let us assume that
some arithmetic function f
is null in zero:
f is declared
Coq < Hypothesis foo : f 0 = 0.
foo is declared
We want to prove the following conditional equality:
As usual, we first get rid of local assumptions with intro
:
1 subgoal
P, Q : nat -> Prop R : nat -> nat -> Prop
f : nat -> nat
foo : f 0 = 0
k : nat
E : k = 0
============================
f k = k
Let us now use equation E
as a left-to-right rewriting:
1 subgoal
P, Q : nat -> Prop R : nat -> nat -> Prop
f : nat -> nat
foo : f 0 = 0
k : nat
E : k = 0
============================
f 0 = 0
This replaced both occurrences of k
by O
.
Now apply foo
will finish the proof:
No more subgoals.
Coq < Qed.
L1 is defined
When one wants to rewrite an equality in a right to left fashion, we should
use rewrite <- E
rather than rewrite E
or the equivalent
rewrite -> E
.
Let us now illustrate the tactic replace
.
f10 is declared
Coq < Lemma L2 : f (f 1) = 0.
1 subgoal
P, Q : nat -> Prop R : nat -> nat -> Prop
f : nat -> nat
foo : f 0 = 0
f10 : f 1 = f 0
============================
f (f 1) = 0
Coq < replace (f 1) with 0.
2 subgoals
P, Q : nat -> Prop R : nat -> nat -> Prop
f : nat -> nat
foo : f 0 = 0
f10 : f 1 = f 0
============================
f 0 = 0
subgoal 2 is:
0 = f 1
What happened here is that the replacement left the first subgoal to be
proved, but another proof obligation was generated by the replace
tactic, as the second subgoal. The first subgoal is solved immediately
by applying lemma foo
; the second one transitivity and then
symmetry of equality, for instance with tactics transitivity
and
symmetry
:
1 subgoal
P, Q : nat -> Prop R : nat -> nat -> Prop
f : nat -> nat
foo : f 0 = 0
f10 : f 1 = f 0
============================
0 = f 1
Coq < transitivity (f 0); symmetry; trivial.
No more subgoals.
In case the equality t=u generated by replace
u with
t is an assumption
(possibly modulo symmetry), it will be automatically proved and the
corresponding goal will not appear. For instance:
1 subgoal
P, Q : nat -> Prop R : nat -> nat -> Prop
f : nat -> nat
foo : f 0 = 0
f10 : f 1 = f 0
============================
f (f 1) = 0
Coq < replace (f 1) with (f 0).
1 subgoal
P, Q : nat -> Prop R : nat -> nat -> Prop
f : nat -> nat
foo : f 0 = 0
f10 : f 1 = f 0
============================
f (f 0) = 0
Coq < replace (f 0) with 0; trivial.
No more subgoals.
Coq < Qed.
L2 is defined
1.5 Using definitions
The development of mathematics does not simply proceed by logical argumentation from first principles: definitions are used in an essential way. A formal development proceeds by a dual process of abstraction, where one proves abstract statements in predicate calculus, and use of definitions, which in the contrary one instantiates general statements with particular notions in order to use the structure of mathematical values for the proof of more specialised properties.
1.5.1 Unfolding definitions
Assume that we want to develop the theory of sets represented as characteristic
predicates over some universe U
. For instance:
U is declared
Variable U is not visible from current goals
Coq < Definition set := U -> Prop.
U is declared
set is defined
Coq < Definition element (x : U) (S : set) := S x.
element is defined
Coq < Definition subset (A B : set) :=
forall x : U, element x A -> element x B.
subset is defined
Now, assume that we have loaded a module of general properties about
relations over some abstract type T
, such as transitivity:
forall x y z : T, R x y -> R y z -> R x z.
transitive is defined
We want to prove that subset
is a transitive
relation.
1 subgoal
P, Q : nat -> Prop R : nat -> nat -> Prop
f : nat -> nat
foo : f 0 = 0
f10 : f 1 = f 0
U : Type
============================
transitive set subset
In order to make any progress, one needs to use the definition of
transitive
. The unfold
tactic, which replaces all
occurrences of a defined notion by its definition in the current goal,
may be used here.
1 subgoal
P, Q : nat -> Prop R : nat -> nat -> Prop
f : nat -> nat
foo : f 0 = 0
f10 : f 1 = f 0
U : Type
============================
forall x y z : set,
subset x y -> subset y z -> subset x z
Now, we must unfold subset
:
1 subgoal
P, Q : nat -> Prop R : nat -> nat -> Prop
f : nat -> nat
foo : f 0 = 0
f10 : f 1 = f 0
U : Type
============================
forall x y z : set,
(forall x0 : U, element x0 x -> element x0 y) ->
(forall x0 : U, element x0 y -> element x0 z) ->
forall x0 : U, element x0 x -> element x0 z
Now, unfolding element
would be a mistake, because indeed a simple proof
can be found by auto
, keeping element
an abstract predicate:
No more subgoals.
Many variations on unfold
are provided in Coq. For instance,
instead of unfolding all occurrences of subset
, we may want to
unfold only one designated occurrence:
1 subgoal
P, Q : nat -> Prop R : nat -> nat -> Prop
f : nat -> nat
foo : f 0 = 0
f10 : f 1 = f 0
U : Type
============================
forall x y z : set,
subset x y ->
(forall x0 : U, element x0 y -> element x0 z) ->
subset x z
One may also unfold a definition in a given local hypothesis, using the
in
notation:
1 subgoal
P, Q : nat -> Prop R : nat -> nat -> Prop
f : nat -> nat
foo : f 0 = 0
f10 : f 1 = f 0
U : Type x, y, z : set
H : subset x y
H0 : forall x : U, element x y -> element x z
============================
subset x z
Coq < unfold subset in H.
1 subgoal
P, Q : nat -> Prop R : nat -> nat -> Prop
f : nat -> nat
foo : f 0 = 0
f10 : f 1 = f 0
U : Type x, y, z : set
H : forall x0 : U, element x0 x -> element x0 y
H0 : forall x : U, element x y -> element x z
============================
subset x z
Finally, the tactic red
does only unfolding of the head occurrence
of the current goal:
1 subgoal
P, Q : nat -> Prop R : nat -> nat -> Prop
f : nat -> nat
foo : f 0 = 0
f10 : f 1 = f 0
U : Type x, y, z : set
H : forall x0 : U, element x0 x -> element x0 y
H0 : forall x : U, element x y -> element x z
============================
forall x0 : U, element x0 x -> element x0 z
Coq < auto.
No more subgoals.
Coq < Qed.
subset_transitive is defined
1.5.2 Principle of proof irrelevance
Even though in principle the proof term associated with a verified lemma corresponds to a defined value of the corresponding specification, such definitions cannot be unfolded in Coq: a lemma is considered an opaque definition. This conforms to the mathematical tradition of proof irrelevance: the proof of a logical proposition does not matter, and the mathematical justification of a logical development relies only on provability of the lemmas used in the formal proof.
Conversely, ordinary mathematical definitions can be unfolded at will, they are transparent.